Safe Food for Canadians Regulations (SOR/2018-108)
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Regulations are current to 2024-11-11 and last amended on 2024-11-08. Previous Versions
SCHEDULE 5(Subsection 200(2) and paragraphs 200(4)(a) and (b))
PART 1Samples
Column 1 | Column 2 | |
---|---|---|
Item | Number of Units in the Lot | Minimum Number of Units in the Sample |
1 | ≥ 2 but ≤ 10 | All the units in the lot |
2 | ≥ 11 but ≤ 128 | 25% of the units in the lot, rounded up to the next whole number, but not less than 10 |
3 | ≥ 129 but ≤ 4 000 | 32 |
4 | ≥ 4 001 but ≤ 8 000 | 64 |
5 | ≥ 8001 but ≤ 12 000 | 96 |
6 | > 12 000 | 125 |
PART 2Formula for Determining the Weighted Average Quantity of the Units in a Sample
For the purposes of paragraph 200(4)(a) of these Regulations, the formula for adjusting the sample mean to determine the weighted average quantity of the units in the sample is as follows:
where
- a
- is the weighted average quantity of the units in the sample;
- is the sample mean calculated as follows:
= ∑x ÷ n
where
- ∑x
- is the sum of the net quantities of all units in the sample;
- s
- is the standard deviation of the sample, calculated as follows:
s = √(∑(x –
)2 ÷ (n – 1))where
- ∑(x – )2
- is the sum of the squared differences between the sample mean and the net quantity of each unit in the sample;
- t
- is the value determined in accordance with Part 3 for the selected sample size; and
- n
- is the number of units in the sample.
Return to footnote *The value of (t ÷ √n) may, instead of being calculated in accordance with this Part, be determined using the applicable value set out in Column 3 of the table to Part 3.
PART 3Table for Values of t and (t ÷ √n)
Column 1 | Column 2 | Column 3 |
---|---|---|
Sample Size | tFootnote for 1 | (t ÷ √n)Footnote for 1 |
2 | 63.657 | 45.01 |
3 | 9.925 | 5.73 |
4 | 5.841 | 2.92 |
5 | 4.604 | 2.06 |
6 | 4.032 | 1.65 |
7 | 3.707 | 1.40 |
8 | 3.499 | 1.24 |
9 | 3.355 | 1.12 |
10 | 3.250 | 1.03 |
11 | 3.169 | 0.955 |
12 | 3.106 | 0.897 |
13 | 3.055 | 0.847 |
14 | 3.012 | 0.805 |
15 | 2.977 | 0.769 |
16 | 2.947 | 0.737 |
17 | 2.921 | 0.708 |
18 | 2.898 | 0.683 |
19 | 2.878 | 0.660 |
20 | 2.861 | 0.640 |
21 | 2.845 | 0.621 |
22 | 2.831 | 0.604 |
23 | 2.819 | 0.588 |
24 | 2.807 | 0.573 |
25 | 2.797 | 0.559 |
26 | 2.787 | 0.547 |
27 | 2.779 | 0.535 |
28 | 2.771 | 0.524 |
29 | 2.763 | 0.513 |
30 | 2.756 | 0.503 |
31 | 2.750 | 0.494 |
32 | 2.746 | 0.485 |
64 | 2.657 | 0.332 |
96 | 2.634 | 0.269 |
125 | 2.615 | 0.234 |
> 32 but < 125, except 64 or 96 | Value of t to be determined by linear interpolationFootnote for 2 | Value of (t ÷ √n) to be determined in accordance with Part 2 |
Return to footnote 1If all units in a lot are selected to constitute a sample, zero must be used as the value of t and (t ÷ √n).
Return to footnote 2The value of t will be determined by linear interpolation as follows:
t = a – ((a – b) × (c – e) ÷ (c – d))
where
- a
- is the value of t for the closest sample size below the selected sample size;
- b
- is the value of t for the closest sample size above the selected sample size;
- c
- is the result of 120 divided by the closest sample size below the selected sample size;
- d
- is the result of 120 divided by the closest sample size above the selected sample size; and
- e
- is the result of 120 divided by the selected sample size.
PART 4Minimum Number of Units for the Purposes of Paragraph 200(4)(b)
Column 1 | Column 2 | |
---|---|---|
Item | Sample Size | Minimum Number of UnitsFootnote for 1 |
1 | ≥ 2 but ≤ 8 | 1 |
2 | ≥ 9 but ≤ 20 | 2 |
3 | ≥ 21 but ≤ 32 | 3 |
4 | ≥ 33 but ≤ 50 | 4 |
5 | ≥ 51 but ≤ 65 | 5 |
6 | ≥ 66 but ≤ 80 | 6 |
7 | ≥ 81 but ≤ 102 | 7 |
8 | ≥ 103 but ≤ 125 | 8 |
Return to footnote 1Minimum number of units in the sample that results in the lot not meeting the requirements of the Act and these Regulations respecting the declaration of net quantity.
- Date modified: